India’s premier institution, the Indian Institutes of Technology has revealed the cut-off marks to be eligible for admission in IIT-JEE 2012.
For the first time in IIT-JEE’ five decade history, the institute revealed minimum qualifying marks in each subject and also in aggregate form for different category of students.
A general category student will have to get 10 % in each subject, other backward class students (OBCs) nine percent and Scheduled Caste (SC), Scheduled Tribe (ST) and Physically Disabled (PD) students five percent.
In addition to these minimum marks, a student will have to clear aggregate cut to be eligible to be part of all India ranking. The aggregate cut-off for general category students is 35 %, for OBCs 31.5 % and SC/ST/PD 17.5 %.
It will mean that if a general category student scores 14 marks out of 136 in all three subjects — Physics, Chemistry and Mathematics — has overall aggregate cut-off of 143 out of total 408 marks, he or she will be eligible for the rank.
According to IIT professors, providing the qualifying marks will help the students to evaluate the performance as soon as they leave the IIT-JEE examination center and will reduce stress on students. It will also help the students in preparing for IIT-JEE examination, said another IIT professor.
Welcoming the move, parent of an aspiring IIT student suggested that the institutes should upload the answer keys of the question papers after the examination. “It will further help the students in evaluating their performance and will also reduce their dependence on coaching centers,” a parent, who was not willing to be quoted as he is a government servant, said.
The decision is a result of the Supreme Court’s observations in a case filed by IIT – Kharagpur professor Rajiv Kumar, who was hailed as a unsung hero for bringing transparency in IIT-JEE examination system.
- by hindustantimes.com